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A color-blind woman marries a man who has normal color vision. What are their chances of having a color-blind daughter? (1) 0% (2) 25% (3) 75% (4) 100%

Question

A color-blind woman marries a man who has normal color vision. What are their chances of having a color-blind daughter?

(1) 0%
(2) 25%
(3) 75%
(4) 100%

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Solution

The chances of a color-blind woman and a man with normal color vision having a color-blind daughter can be determined by understanding the inheritance pattern of color blindness.

Color blindness is a sex-linked recessive trait, which means it is carried on the X chromosome. Females have two X chromosomes (XX), while males have one X and one Y chromosome (XY).

In this case, the color-blind woman is homozygous for the color blindness allele (XcXc), as she has normal color vision. The man with normal color vision is homozygous for the normal allele (XNXN).

When they have children, the daughter will inherit one X chromosome from each parent. Since the color-blind woman only has the color blindness allele (Xc), she can only pass on the Xc allele to her daughter. The man can only pass on the normal allele (XN) to his daughter.

Therefore, the daughter will be a carrier of the color blindness allele (XcXN), but she will not be color blind herself.

Based on this information, the chances of the couple having a color-blind daughter is 0% (option 1).

This problem has been solved

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