Select the correct answerIf (a + b)/ c = 6/5 and (b + c ) / a = 9/2 then what is the value of (a + c )/b?

To solve this problem, we need to use the given equations and manipulate them to find the value of (a + c) / b.

Given:

1. (a + b) / c = 6/5
2. (b + c) / a = 9/2

First, let's isolate 'b' in the first equation: b = c * 6/5 - a

Then, substitute 'b' from the first equation into the second equation: (c * 6/5 - a + c) / a = 9/2 Simplify to: (6c/5 + c - a) / a = 9/2 Multiply both sides by 'a' to get rid of the denominator: 6c/5 + c - a = 9a/2 Simplify to: 11c/5 - a = 9a/2 Multiply both sides by 5 to get rid of the denominator: 11c - 5a = 45a/2 Simplify to: 11c = 50a So, c = 50a/11

Now, substitute 'c' from the third equation into the first equation: (a + 50a/11) / (50a/11) = 6/5 Simplify to: (61a/11) / (50a/11) = 6/5 Simplify to: 61/50 = 6/5 This is a contradiction, so there is no solution to the system of equations. Therefore, the value of (a + c) / b cannot be determined.