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If a = bq + r where b = 3, then any integer can be expressed as a =3q, 3q + 1, 3q +2    Only 3qOnly 3q + 1None of the above

Question

If a = bq + r where b = 3, then any integer can be expressed as a = 3q, 3q + 1, 3q + 2

  • Only 3q
  • Only 3q + 1
  • None of the above
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Solution

The statement "any integer can be expressed as a =3q, 3q + 1, 3q +2" is correct. This is because the equation a = bq + r is the formula for Euclidean division, where a is the dividend, b is the divisor, q is the quotient, and r is the remainder.

In this case, b is given as 3. Therefore, for any integer a, when divided by 3, the remainder r can only be 0, 1, or 2. This is because the remainder is always less than the divisor.

So, any integer a can be expressed as 3q (when the remainder is 0), 3q + 1 (when the remainder is 1), or 3q + 2 (when the remainder is 2).

Therefore, the correct answer is "any integer can be expressed as a =3q, 3q + 1, 3q +2".

This problem has been solved

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