Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
Question
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
Solution
Let's denote the three consecutive odd integers as x, x+2, and x+4.
According to the problem, three times the first integer is 3 more than twice the third. We can write this as an equation:
3x = 2(x+4) + 3
Solving this equation will give us the value of x, which represents the first integer.
First, distribute the 2 on the right side of the equation:
3x = 2x + 8 + 3
Then, simplify the right side:
3x = 2x + 11
Next, subtract 2x from both sides to isolate x:
x = 11
So, the first integer is 11.
The third integer, then, is x+4, or 11+4, which equals 15.
Therefore, the third integer is 15.
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