Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
Question
Solution 1
Let's denote the three consecutive odd integers as x, x+2, and x+4.
According to the problem, three times the first integer is 3 more than twice the third. We can write this as an equation:
3x = 2(x+4) + 3
Solving this equation will give us the value of x, which represents the first integer.
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