The cork in a bottle is 2.00 cm in diameter. If the pressure inside the bottle is 3.00 atm, then the net force on the cork due to the pressure difference is
Question
The cork in a bottle is 2.00 cm in diameter. If the pressure inside the bottle is 3.00 atm, then the net force on the cork due to the pressure difference is
Solution
To solve this problem, we need to use the formula for pressure which is P = F/A, where P is the pressure, F is the force, and A is the area. We need to rearrange the formula to solve for F, so F = P * A.
Step 1: Convert the diameter of the cork to radius. The radius is half of the diameter, so the radius is 1.00 cm or 0.01 m.
Step 2: Calculate the area of the cork. The formula for the area of a circle is A = πr^2. Substituting the radius into the formula gives A = π * (0.01 m)^2 = 0.000314 m^2.
Step 3: Convert the pressure from atm to Pa. 1 atm is approximately 101325 Pa, so 3.00 atm is 3.00 * 101325 Pa = 303975 Pa.
Step 4: Substitute the pressure and area into the formula for force. F = P * A = 303975 Pa * 0.000314 m^2 = 95.45 N.
So, the net force on the cork due to the pressure difference is 95.45 N.
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