The relationship between the force F and position x of a body is as shown in the figure. The work done in displacing the body from x = 1 m to x = 5 m will be:

To solve the problem regarding the work done in displacing the body from $x = 1 \, \text{m}$ to $x = 5 \, \text{m}$, we follow these steps. However, due to the lack of a provided figure, I will outline the general approach.

1. ### Break Down the Problem

1. Identify the shape of the graph relating force $F$ to position $x$.
2. Determine the areas under the curve of the graph from $x = 1 \, \text{m}$ to $x = 5 \, \text{m}$.
3. Calculate the total work done based on the identified areas.

2. ### Relevant Concepts

The work done $W$ by a force can be calculated as the area under the force-position graph: $W = \int_{x_1}^{x_2} F(x) \, dx$ where $x_1 = 1 \, \text{m}$ and $x_2 = 5 \, \text{m}$.

3. ### Analysis and Detail

1. Identify the areas:

   • If the graph is linear, find the equation of the line (if necessary) and calculate the area triangles or rectangles.
   • If the graph includes segments (like horizontal, vertical, or sloped lines), break them into respective geometrical shapes.

2. Calculate the areas:

   • For rectangles: Area $A = \text{base} \times \text{height}$
   • For triangles: Area $A = \frac{1}{2} \times \text{base} \times \text{height}$
   • Sum the areas to find the total work done.

4. ### Verify and Summarize

1. After calculating the areas, ensure that each step calculates the respective areas correctly.
2. Add the areas together to find the total work done.

Final Answer

The total work done in displacing the body from $x = 1 \, \text{m}$ to $x = 5 \, \text{m}$ is the sum of the areas calculated under the force-position graph regarding those limits. Please substitute in the appropriate values from your graph once available.