What is Δn for the reaction below:2H2O(l) ⟶ 2H2(g) + O2(g) Group of answer choices-11-33
Question
What is Δn for the reaction below:
Group of answer choices
- -1
- -3
Solution
Δn is the change in the number of moles of gas in a chemical reaction. It is calculated as the number of moles of gaseous products minus the number of moles of gaseous reactants.
In the reaction 2H2O(l) ⟶ 2H2(g) + O2(g), the number of moles of gaseous products is 2 (for H2) + 1 (for O2) = 3.
Since there are no gaseous reactants (H2O is in liquid state), the number of moles of gaseous reactants is 0.
Therefore, Δn = 3 - 0 = 3.
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