What is the  ΔG° at room temperature of the reaction 2CO+O2→2CO2, if ΔH°=-128.3 kJ and   ΔS°= - 159.5 J/K ?*- 80. 769 kJ80. 769 kJ- 175.831 kJ- 124.313 kJ

Question

What is the  ΔG° at room temperature of the reaction 2CO+O2→2CO2, if ΔH°=-128.3 kJ and   ΔS°= - 159.5 J/K ?*- 80. 769 kJ80. 769 kJ- 175.831 kJ- 124.313 kJ
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Solution 1

To calculate the ΔG° at room temperature for the reaction 2CO+O2→2CO2, we can use the Gibbs free energy equation:

ΔG° = ΔH° - TΔS°

Given that ΔH° = -128.3 kJ (or -128300 J to match the units of ΔS°) and ΔS° = -159.5 J/K, we can substitute these values into the equation.

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