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한 제조공정의 표준편차는 0.005이고, 규격은 0.99± 0.02로 주어져 있다.(1) 공정평균이 0.99로 목표값(Target)과 일치할 때, 공정능력지수 와 및 시그마 수준을 구하라.(2) 공정평균이 1.00으로 이동한 경우, 와 및 시그마 수준을 구하라.

Question

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Solution

1. Break Down the Problem

We need to calculate the following:

  1. Process Capability Index Cp C_p
  2. Process Capability Index Cpk C_{pk}
  3. Sigma level for two scenarios:
    • When the process average is 0.99
    • When the process average is 1.00

2. Relevant Concepts

  1. The formulas for process capability indices are: Cp=USLLSL6σ C_p = \frac{USL - LSL}{6\sigma} Cpk=min(Cpu,Cpl) C_{pk} = \min{(C_{pu}, C_{pl})} where:
    • USL USL = Upper Specification Limit
    • LSL LSL = Lower Specification Limit
    • σ \sigma = Standard deviation
    • Cpu=USLμ3σ C_{pu} = \frac{USL - \mu}{3\sigma}
    • Cpl=μLSL3σ C_{pl} = \frac{\mu - LSL}{3\sigma}

3. Analysis and Detail

Given Data:

  • Standard deviation σ=0.005 \sigma = 0.005
  • Target (process mean) when it matches = 0.99
  • Upper Specification Limit (USL) = 0.99 + 0.02 = 1.01
  • Lower Specification Limit (LSL) = 0.99 - 0.02 = 0.97

(1) When Process Mean is 0.99

  1. Calculate Cp C_p : Cp=1.010.976×0.005=0.040.03=1.33 C_p = \frac{1.01 - 0.97}{6 \times 0.005} = \frac{0.04}{0.03} = 1.33

  2. Calculate Cpu C_{pu} and Cpl C_{pl} :

    • Cpu C_{pu} : Cpu=1.010.993×0.005=0.020.015=1.33 C_{pu} = \frac{1.01 - 0.99}{3 \times 0.005} = \frac{0.02}{0.015} = 1.33
    • Cpl C_{pl} : Cpl=0.990.973×0.005=0.020.015=1.33 C_{pl} = \frac{0.99 - 0.97}{3 \times 0.005} = \frac{0.02}{0.015} = 1.33
  3. Thus, Cpk C_{pk} : Cpk=min(Cpu,Cpl)=min(1.33,1.33)=1.33 C_{pk} = \min{(C_{pu}, C_{pl})} = \min{(1.33, 1.33)} = 1.33

  4. Sigma Level: Sigma Level=Cp×3=1.33×3=4.00 \text{Sigma Level} = C_p \times 3 = 1.33 \times 3 = 4.00

(2) When Process Mean is 1.00

  1. Calculate Cp C_p (remains the same): Cp=1.010.976×0.005=0.040.03=1.33 C_p = \frac{1.01 - 0.97}{6 \times 0.005} = \frac{0.04}{0.03} = 1.33

  2. Calculate Cpu C_{pu} and Cpl C_{pl} :

    • Cpu C_{pu} : Cpu=1.011.003×0.005=0.010.015=0.67 C_{pu} = \frac{1.01 - 1.00}{3 \times 0.005} = \frac{0.01}{0.015} = 0.67
    • Cpl C_{pl} : Cpl=1.000.973×0.005=0.030.015=2.00 C_{pl} = \frac{1.00 - 0.97}{3 \times 0.005} = \frac{0.03}{0.015} = 2.00
  3. Thus, Cpk C_{pk} : Cpk=min(Cpu,Cpl)=min(0.67,2.00)=0.67 C_{pk} = \min{(C_{pu}, C_{pl})} = \min{(0.67, 2.00)} = 0.67

  4. Sigma Level: Sigma Level=Cp×3=1.33×3=4.00 \text{Sigma Level} = C_p \times 3 = 1.33 \times 3 = 4.00

4. Verify and Summarize

  • For the process mean of 0.99:
    • Cp=1.33 C_p = 1.33 , Cpk=1.33 C_{pk} = 1.33 , Sigma Level = 4.00
  • For the process mean of 1.00:
    • Cp=1.33 C_p = 1.33 , Cpk=0.67 C_{pk} = 0.67 , Sigma Level = 4.00

Final Answer

  1. When Process Mean is 0.99:

    • Cp=1.33 C_p = 1.33
    • Cpk=1.33 C_{pk} = 1.33
    • Sigma Level = 4.00
  2. When Process Mean is 1.00:

    • Cp=1.33 C_p = 1.33
    • Cpk=0.67 C_{pk} = 0.67
    • Sigma Level = 4.00

This problem has been solved

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