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A 0.016 kg record with a radius of 15 cm rotates with an angular speed of 28 rpm. Find the angular momentum of the record.

Question

A 0.016 kg record with a radius of 15 cm rotates with an angular speed of 28 rpm. Find the angular momentum of the record.

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Solution

Sure, here are the steps to find the angular momentum of the record:

Step 1: Convert the angular speed from revolutions per minute (rpm) to radians per second.

1 revolution = 2π radians, and 1 minute = 60 seconds.

So, 28 rpm = 28 * 2π / 60 rad/s ≈ 2.93 rad/s.

Step 2: The moment of inertia (I) for a disk is given by the formula I = 0.5 * m * r^2, where m is the mass and r is the radius.

Substitute the given values into the formula: I = 0.5 * 0.016 kg * (0.15 m)^2 ≈ 0.00018 kg*m^2.

Step 3: The angular momentum (L) is given by the formula L = I * ω, where I is the moment of inertia and ω is the angular speed.

Substitute the values from steps 1 and 2 into this formula: L = 0.00018 kgm^2 * 2.93 rad/s ≈ 0.00053 kgm^2/s.

So, the angular momentum of the record is approximately 0.00053 kg*m^2/s.

This problem has been solved

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