A torque of 0.154 N*m is applied to an egg beater. If the egg beater starts at rest, what is its angular momentum after 0.504 s?
Question
A torque of 0.154 N*m is applied to an egg beater.
If the egg beater starts at rest, what is its angular momentum after 0.504 s?
Solution
To solve this problem, we need to use the formula for angular momentum (L) which is the product of the torque (τ) and the time (t) it is applied for. This is based on the principle of conservation of angular momentum, and assumes no other torques are acting on the egg beater.
The formula is: L = τ * t
Given: τ = 0.154 N*m (torque) t = 0.504 s (time)
Substitute these values into the formula:
L = 0.154 Nm * 0.504 s = 0.077616 Nm*s
So, the angular momentum of the egg beater after 0.504 s is 0.077616 Nms.
Similar Questions
A 0.016 kg record with a radius of 15 cm rotates with an angular speed of 28 rpm. Find the angular momentum of the record.
A ball on a string spins in a horizontal circle of radius 2.5 m with a speed of 3.0 m/s. The tension in the string is 5.4 N. What is the mass of the ball?
A net force of 5. 84 N accelerates a cart of mass 3.32 kg. What is the acceleration of the trolley in m/s2, correct to 1 decimal place?
A body of moment of inertia 2 kg m2 is rotated at a speed of 25 rad s–1. A tangential force at rim stops the wheel in10 s. Average torque of force
A mass of 2 kg at rest travels for 4 sec with an acceleration of 1.5 m/s2. What is the gain of momentum?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.