Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is36 m. Find the dimensions of the garden
Question
Problem Statement
Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.
Solution
Let's denote the width of the garden as x (in meters). According to the problem, the length of the garden is x + 4 meters.
The perimeter of a rectangle is calculated as 2*(length + width). In this case, half of the perimeter is given as 36 meters. So, we can set up the following equation:
36 = x + (x + 4)
Solving this equation will give us the dimensions of the garden.
Step 1: Simplify the equation 36 = 2x + 4
Step 2: Subtract 4 from both sides of the equation 32 = 2x
Step 3: Divide both sides of the equation by 2 x = 16
So, the width of the garden is 16 meters. The length of the garden is x + 4 = 16 + 4 = 20 meters.
Therefore, the dimensions of the garden are 16 meters by 20 meters.
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