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The length of a rectangle is 4 in longer than its width.If the perimeter of the rectangle is 52 in, find its length and width.

Question

The length of a rectangle is 4 in longer than its width.

If the perimeter of the rectangle is 52 in, find its length and width.

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Solution

Sure, let's solve this step by step.

Step 1: Let's denote the width of the rectangle as x (in inches). Therefore, the length of the rectangle is x + 4 (in inches).

Step 2: The formula for the perimeter of a rectangle is 2*(length + width). In this case, it's given as 52 inches. So, we can set up the equation as follows: 2*(x + (x + 4)) = 52.

Step 3: Simplify the equation. This gives us 2*(2x + 4) = 52.

Step 4: Distribute the 2 on the left side of the equation. This gives us 4x + 8 = 52.

Step 5: Subtract 8 from both sides of the equation. This gives us 4x = 44.

Step 6: Divide both sides of the equation by 4. This gives us x = 11. So, the width of the rectangle is 11 inches.

Step 7: Substitute x = 11 into the length equation (x + 4). This gives us 11 + 4 = 15. So, the length of the rectangle is 15 inches.

So, the width of the rectangle is 11 inches and the length is 15 inches.

This problem has been solved

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