Which one of the following numbers will completely divide(328 + 329 + 330 + 331)? 26162930

To solve this problem, we first need to understand that the sum of four consecutive numbers is always divisible by 4. This is because the four numbers can be represented as (n-1), n, (n+1), (n+2) and their sum is 4n which is divisible by 4.

So, the sum of 328, 329, 330, and 331 is 1318, which is divisible by 4.

Now, we need to check if 1318 is divisible by 26162930.

To do this, we divide 1318 by 26162930. If the remainder is 0, then 1318 is divisible by 26162930.

However, 26162930 is much larger than 1318, so 1318 cannot be divided by 26162930 without a remainder.

Therefore, 26162930 will not completely divide the sum of 328, 329, 330, and 331.