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A material has Poisson's ratio 0.50. If a uniform rod of it suffers a longitudinal strain of 2×10−32×10-3, then the percentage change in volume is

Question

A material has Poisson's ratio 0.50. If a uniform rod of it suffers a longitudinal strain of 2×10−3, then the percentage change in volume is

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Solution

The Poisson's ratio (ν) is a measure of the Poisson effect, that describes the expansion or contraction of a material in directions perpendicular to the direction of loading. The formula for Poisson's ratio is:

ν = - (Transverse Strain / Longitudinal Strain)

Given that Poisson's ratio (ν) is 0.50 and the longitudinal strain is 2×10^-3, we can find the transverse strain using the formula:

Transverse Strain = - ν * Longitudinal Strain Transverse Strain = - 0.50 * 2×10^-3 = -1×10^-3

The change in volume (ΔV) for a small strain is given by the formula:

ΔV/V = Longitudinal Strain + 2 * Transverse Strain

Substituting the given values:

ΔV/V = 2×10^-3 + 2 * -1×10^-3 = 0

So, the percentage change in volume is 0%.

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