Knowee
Questions
Features
Study Tools

An aluminum ball is subjected to a pressure of 7.00 × 106 Pa. The volume strain is −1.0 × 10−4. What is the bulk modulus?

Question

An aluminum ball is subjected to a pressure of 7.00 × 10^6 Pa. The volume strain is −1.0 × 10^−4. What is the bulk modulus?

🧐 Not the exact question you are looking for?Go ask a question

Solution

The bulk modulus (K) of a substance measures the substance's resistance to uniform compression. It is defined as the ratio of the infinitesimal pressure increase to the resulting relative decrease of the volume.

The formula for bulk modulus (K) is:

K = -P / ΔV/V

where:

  • P is the pressure change,
  • ΔV is the change in volume,
  • V is the original volume.

Given in the problem:

  • P = 7.00 × 10^6 Pa (pressure change)
  • ΔV/V = -1.0 × 10^-4 (volume strain)

Substitute these values into the formula:

K = - (7.00 × 10^6 Pa) / (-1.0 × 10^-4)

Solving this gives:

K = 7.00 × 10^10 Pa

So, the bulk modulus of the aluminum ball is 7.00 × 10^10 Pa.

This problem has been solved

Similar Questions

A wire of length 4 meters is stretched by a force of 800 N, resulting in a strain of 0.02. What is the Young's modulus of the material?

A material has Poisson's ratio 0.50. If a uniform rod of it suffers a longitudinal strain of 2×10−32×10-3, then the percentage change in volume is

A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?

The diameter of a brass rod is 0.2 mm and Young’s modulus of brass is 9 x 1010 N/m2. The force required to stretch by 1% of its length is kππ newton. Find k.

An ore contains 7.8% aluminium. What mass of aluminium would there be in 50kg of the ore?

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.