A heat engine has an efficiency of 35.0% and receives 150 J of heat per cycle. How much work does it perform in each cycle?
Question
Solution
The efficiency of a heat engine is given by the ratio of the work done (W) to the heat input (Q). This can be expressed as:
Efficiency = W/Q
We can rearrange this formula to solve for the work done:
W = Efficiency * Q
Given that the efficiency of the engine is 35.0% (or 0.35 in decimal form) and the heat input is 150 J, we can substitute these values into the formula:
W = 0.35 * 150
W = 52.5 J
So, the engine performs 52.5 Joules of work in each cycle.
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