Some green is blue. No blue is white.Choose Onea) Some green is whiteb) No white is greenc) No green is whited) None of the abovee) Skip

To solve this logic puzzle, let's analyze the given statements step by step.

1. Break Down the Problem

• Statement 1: Some green is blue.
• Statement 2: No blue is white.

2. Relevant Concepts

We need to determine the relationship between green, blue, and white based on the provided statements. Here are the implications:

• From Statement 1, we can say that there exists at least some green objects that are also blue.
• From Statement 2, since no blue object can be white, it follows that any green object that is blue cannot be white.

3. Analysis and Detail

1. Interpret Statement 1: Some green objects belong to the set of blue objects. Let's denote:

   • G = set of green objects
   • B = set of blue objects
   • W = set of white objects
   • From the first statement, $G \cap B \neq \emptyset$

2. Interpret Statement 2: No blue object is white. Therefore, we can say:

   • $B \cap W = \emptyset$
   • This means that any object that is blue cannot also be white.

3. Combining the Information: Since some green is blue and no blue is white, this leads us to conclude that:

   • The parts of green that are blue cannot be white. Hence, some green cannot be white.

4. Verify and Summarize

Now, we need to verify against the options:

• a) Some green is white: This is not true because some green is blue, and no blue is white.
• b) No white is green: This cannot be concluded definitively since we do not know the relationship of non-blue greens to white.
• c) No green is white: This is also not definitively true; it is possible that there are greens that are not blue and could be white, we just have information that those greens which are blue cannot be white.
• d) None of the above: This option may be true as we cannot definitively conclude options a, b, or c.

Final Answer

The most reasonable choice based on the analysis is: d) None of the above.