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Given the code fragment:int x=100;int a=x++;int b=++x;int c=x++;int d= (a<b) ? (a<c) ? a: (b<c) ? b : c;what is the result?A100B101C102D103ECompilation fails

Question

Given the code fragment:

int x=100;
int a=x++;
int b=++x;
int c=x++;
int d= (a&lt;b) ? (a&lt;c) ? a: (b&lt;c) ? b : c;

what is the result? A 100 B 101
C 102
D 103
E Compilation fails

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Solution

The code fragment is written in Java. Let's break it down:

  1. int x=100; This line initializes an integer variable x with a value of 100.
  2. int a=x++; This line initializes an integer variable a with the current value of x (which is 100), then increments x by 1. So, a is 100 and x is now 101.
  3. int b=++x; This line increments x by 1 first (making x 102), then initializes an integer variable b with the new value of x. So, b is 102.
  4. int c=x++; This line initializes an integer variable c with the current value of x (which is 102), then increments x by 1. So, c is 102 and x is now 103.
  5. int d= (a<b) ? (a<c) ? a: (b<c) ? b : c; This line uses the ternary operator ? : to assign a value to d. It first checks if a is less than b. If true, it then checks if a is less than c. If true, d is assigned the value of a. If false, it checks if b is less than c. If true, d is assigned the value of b. If false, d is assigned the value of c. In this case, a is 100, b is 102, and c is 102. So, d is assigned the value of a, which is 100.

So, the result is A100.

This problem has been solved

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