Show that, when a charge of 180 000 C passes through the battery, the total amount of energy transferred to the battery is about 70 MJ.

To solve this problem, we need to use the formula for electrical energy, which is:

E = QV

where: E is the energy transferred, Q is the charge, V is the voltage.

We know that Q = 180,000 C, but we don't know the voltage V. However, we can find it out from the information given in the problem.

The problem states that the total energy transferred to the battery is about 70 MJ (Mega Joules). We can convert this to Joules by multiplying by 1,000,000 (since 1 MJ = 1,000,000 J), so E = 70,000,000 J.

Now we can substitute E and Q into the formula and solve for V:

70,000,000 J = 180,000 C * V

Divide both sides by 180,000 C to solve for V:

V = 70,000,000 J / 180,000 C = 388.89 V

So, the voltage of the battery is approximately 388.89 V.

Now, we can check our answer by substitifying V back into the formula:

E = QV = 180,000 C * 388.89 V = 69,999,820 J, which is approximately 70 MJ.

Therefore, when a charge of 180,000 C passes through the battery, the total amount of energy transferred to the battery is indeed about 70 MJ.