The cross product of two vectors A and B is given by the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors i, j, and k. The second row is the coefficients of the vector A, and the third row is the coefficients of the vector B.

So, for A = 2i – 3j + 2k and B = i – 3k, the matrix would look like this:

| i j k |
| 2 -3 2 |
| 1 0 -3 |

The cross product, A x B, is then calculated as follows:

A x B = i(-3*-3 - 2*0) - j(2*-3 - 2*1) + k(2*0 - -3*1)
= i(9 - 0) - j(-6 - 2) + k(0 - -3)
= 9i + 8j + 3k

So, the cross product of A and B is 9i + 8j + 3k.

Question

The cross product of two vectors A and B is given by the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors i, j, and k. The second row is the coefficients of the vector A, and the third row is the coefficients of the vector B.

So, for A = 2i – 3j + 2k and B = i – 3k, the matrix would look like this:

| i  j  k |
| 2 -3  2 |
| 1  0 -3 |

The cross product, A x B, is then calculated as follows:

A x B = i(-3*-3 - 2*0) - j(2*-3 - 2*1) + k(2*0 - -3*1)
      = i(9 - 0) - j(-6 - 2) + k(0 - -3)
      = 9i + 8j + 3k

So, the cross product of A and B is 9i + 8j + 3k.

Knowee AI · Accepted Answer

The cross product of two vectors A and B is given by the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors i, j, and k. The second row is the coefficients of the vector A, and the third row is the coefficients of the vector B.

So, for A = 2i – 3j + 2k and B = i – 3k, the matrix would look like this:

| i  j  k |
| 2 -3  2 |
| 1  0 -3 |

The cross product, A x B, is then calculated as follows:

A x B = i(-3*-3 - 2*0) - j(2*-3 - 2*1) + k(2*0 - -3*1)
      = i(9 - 0) - j(-6 - 2) + k(0 - -3)
      = 9i + 8j + 3k

So, the cross product of A and B is 9i + 8j + 3k.

Find the cross product of A and B if A = 2i – 3j + 2k and B = i – 3kGroup of answer choices9i + 8j + 3ki – 3k8i + 3j + 9k9i + 3j + 8k

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