How many joules of heat are required to raise the temperature of 20.0 grams of water from 30.0°C to 40.0°C?A 42 JB 84 JC 420 JD 840 J
Question
How many joules of heat are required to raise the temperature of 20.0 grams of water from 30.0°C to 40.0°C?
- A) 42 J
- B) 84 J
- C) 420 J
- D) 840 J
Solution
To solve this problem, we need to use the formula for heat transfer:
Q = mcΔT
where: Q = heat energy (Joules) m = mass (grams) c = specific heat capacity (Joules/gram °C) ΔT = change in temperature (°C)
For water, the specific heat capacity (c) is 4.18 J/g°C.
Given: m = 20.0 g ΔT = 40.0°C - 30.0°C = 10.0°C
Substituting these values into the formula, we get:
Q = (20.0 g)(4.18 J/g°C)(10.0°C) = 836 J
So, the closest answer is D. 840 J.
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