It seems like there's a mistake in the question. The roots of the polynomial s^2 + 4s + 8 can be found using the quadratic formula, which is:

s = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 1, b = 4, and c = 8.

Substituting these values into the formula gives:

s = [-4 ± sqrt((4)^2 - 4*1*8)] / (2*1)
s = [-4 ± sqrt(16 - 32)] / 2
s = [-4 ± sqrt(-16)] / 2
s = [-4 ± 4i] / 2
s = -2 ± 2i

So, the roots of the polynomial s^2 + 4s + 8 are -2 + 2i and -2 - 2i.

Question

It seems like there's a mistake in the question. The roots of the polynomial s^2 + 4s + 8 can be found using the quadratic formula, which is:

s = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 1, b = 4, and c = 8.

Substituting these values into the formula gives:

s = [-4 ± sqrt((4)^2 - 4*1*8)] / (2*1)
s = [-4 ± sqrt(16 - 32)] / 2
s = [-4 ± sqrt(-16)] / 2
s = [-4 ± 4i] / 2
s = -2 ± 2i

So, the roots of the polynomial s^2 + 4s + 8 are -2 + 2i and -2 - 2i.

Knowee AI · Accepted Answer

It seems like there's a mistake in the question. The roots of the polynomial s^2 + 4s + 8 can be found using the quadratic formula, which is:

s = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 1, b = 4, and c = 8.

Substituting these values into the formula gives:

s = [-4 ± sqrt((4)^2 - 4*1*8)] / (2*1)
s = [-4 ± sqrt(16 - 32)] / 2
s = [-4 ± sqrt(-16)] / 2
s = [-4 ± 4i] / 2
s = -2 ± 2i

So, the roots of the polynomial s^2 + 4s + 8 are -2 + 2i and -2 - 2i.

The roots of the polynomial s2+4s+8𝑠2+4𝑠+8 are−4−4 and −2−2−2j−2𝑗 and 2j2𝑗−2+2j−2+2𝑗 and −2−2j−2−2𝑗−2−2 and −2