A Lossless transmission line of length 50cm with L = 10microH/m, C=40pF/m is operated at 30MHz,its electrical length isSelect one:a. 40πb. 1.88c. 108od. 0.2λ

To find the electrical length of the transmission line, we can use the formula:

Electrical length = (2π * frequency * physical length) / velocity factor

First, let's calculate the velocity factor. The velocity factor is given by the formula:

Velocity factor = 1 / √(LC)

Given that L = 10 microH/m and C = 40 pF/m, we can calculate the velocity factor as follows:

Velocity factor = 1 / √(10 * 10^(-6) * 40 * 10^(-12)) = 1 / √(400 * 10^(-18)) = 1 / (20 * 10^(-9)) = 1 / 2 * 10^(-8) = 5 * 10^7

Now, let's calculate the electrical length using the formula mentioned earlier:

Electrical length = (2π * frequency * physical length) / velocity factor = (2π * 30 * 10^6 * 0.5) / (5 * 10^7) = (2π * 30 * 10^6 * 0.5) / (5 * 10^7) = π * 30 * 10^6 / (5 * 10^7) = 6π / 5 ≈ 3.77

Therefore, the electrical length of the transmission line is approximately 3.77.