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Solve this quadratic equation by completing the square.x2 + 6x – 10 = 0A.B.C.D.

Question

Solve this quadratic equation by completing the square.

x2+6x10=0 x^2 + 6x - 10 = 0
A.
B.
C.
D.

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Solution

1. Break Down the Problem

To solve the quadratic equation x2+6x10=0x^2 + 6x - 10 = 0 by completing the square, we need to isolate the variable xx.

2. Relevant Concepts

The method of completing the square involves transforming the quadratic equation into a perfect square trinomial. We use the following form:

x2+bx+c=(x+d)2e x^2 + bx + c = (x + d)^2 - e

where dd and ee represent adjustments made to complete the square.

3. Analysis and Detail

Start with the equation:

x2+6x10=0 x^2 + 6x - 10 = 0

  1. Move the constant term to the other side:

    x2+6x=10 x^2 + 6x = 10

  2. Complete the square:

    • Take half of the coefficient of xx (which is 6), and square it:

      (62)2=32=9 \left(\frac{6}{2}\right)^2 = 3^2 = 9

    • Add 9 to both sides:

      x2+6x+9=10+9 x^2 + 6x + 9 = 10 + 9

      (x+3)2=19 (x + 3)^2 = 19

4. Verify and Summarize

Now, we will take the square root of both sides:

x+3=±19 x + 3 = \pm \sqrt{19}

Finally, isolate xx:

x=3±19 x = -3 \pm \sqrt{19}

The two solutions can therefore be expressed as:

x=3+19andx=319 x = -3 + \sqrt{19} \quad \text{and} \quad x = -3 - \sqrt{19}

Final Answer

The solutions to the equation x2+6x10=0x^2 + 6x - 10 = 0 are:

x=3+19andx=319 x = -3 + \sqrt{19} \quad \text{and} \quad x = -3 - \sqrt{19}

This problem has been solved

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