Identify the correct Lewis structure of CO2. Ensure that all charges and lone pairs are shown.Group of answer choices
Question
Identify the correct Lewis structure of CO2. Ensure that all charges and lone pairs are shown.
Group of answer choices
Solution
The Lewis structure for CO2 (Carbon Dioxide) is as follows:
-
Carbon (C) is the central atom, which is surrounded by two Oxygen (O) atoms.
-
Carbon has 4 valence electrons and Oxygen has 6. Since there are two Oxygen atoms, we have a total of 16 valence electrons for the CO2 Lewis structure.
-
Carbon is the least electronegative atom and goes in the center of this structure.
-
We put the Carbon in the center and the Oxygen atoms on the sides.
-
We then distribute the 16 electrons around the atoms, starting from the outside atoms first (Oxygen), and then moving to the central atom (Carbon).
-
Each Oxygen atom needs 8 electrons to fulfill its octet. It already has 6, so it needs 2 more. Carbon also needs 8 electrons, and it currently has 4.
-
We can form two double bonds between Carbon and Oxygen to fulfill the octet rule for all atoms.
-
The final structure is O=C=O.
There are no charges on the atoms because all atoms have their octet satisfied. There are also no lone pairs on the Carbon atom, but there are 2 lone pairs on each Oxygen atom.
Similar Questions
Identify the correct Lewis structure of CF4. Ensure that all charges and lone pairs are shown.Group of answer choices
Identify the correct Lewis structure of CCl4. Ensure that all charges and lone pairs are shown.
Draw the Lewis structure for carbon dioxide, CO2 . Determine the shape and polarity of this molecule from the Lewis structure you created.
In the Lewis dot structure for water, how many shared pairs of electrons are there?Group of answer choices4062
Lewis dot structure of carbon monoxide is 𝐶°°=←𝑂°° Formal charge on oxygen atom in the molecule is
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.