How many grams of FeSO4 dissolved per litre gives 210.5 ppm hardness? ( Fe=56, S=32, O=16)a.100 mg/lb.210.5 mg/lc.286.28 mg/ld.136 mg/l
Question
How many grams of FeSO4 dissolved per litre gives 210.5 ppm hardness?
( Fe=56, S=32, O=16)
a. 100 mg/l
b. 210.5 mg/l
c. 286.28 mg/l
d. 136 mg/l
Solution
The molecular weight of FeSO4 is calculated as follows:
Fe = 56 S = 32 O4 = 16*4 = 64
So, the molecular weight of FeSO4 = 56 + 32 + 64 = 152 g/mol
PPM means parts per million, so 210.5 ppm hardness means there are 210.5 mg of FeSO4 in 1 litre of water.
To convert this to grams per litre, we divide by 1000 (since there are 1000 mg in a gram):
210.5 mg/L = 210.5/1000 g/L = 0.2105 g/L
So, the answer is 0.2105 g/L of FeSO4 gives 210.5 ppm hardness.
Therefore, none of the options provided (a.100 mg/l, b.210.5 mg/l, c.286.28 mg/l, d.136 mg/l) are correct.
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