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(43, 54, 55, 55, 55, 34, 34, 34) In the given numbers, 55 is considered to be thea.Raw scoreb.Modec.Meand.Median

Question

In the given numbers, 55 is considered to be the:

  • a. Raw score
  • b. Mode
  • c. Mean
  • d. Median
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Solution

Break Down the Problem

  1. Identify the definitions of raw score, mode, mean, and median.
  2. Analyze the provided set of numbers: (43, 54, 55, 55, 55, 34, 34, 34).
  3. Determine which of these statistical measures is represented by the number 55.

Relevant Concepts

  1. Raw Score: The original score before any transformations or calculations.
  2. Mode: The number that appears most frequently in a data set.
  3. Mean: The average of the numbers, calculated by summing all values and dividing by the count of values.
  4. Median: The middle number when the data set is ordered from least to greatest.

Analysis and Detail

  1. Raw Score: 55 is a raw score in this context, but it does not define it specifically.

  2. Mode Calculation: In the dataset (43, 54, 55, 55, 55, 34, 34, 34), the numbers and their frequencies are:

    • 43: 1 time
    • 54: 1 time
    • 55: 3 times
    • 34: 3 times The mode is 55 because it appears more frequently than any other number.
  3. Mean Calculation: Mean=43+54+55+55+55+34+34+348=43+54+55+55+55+34+34+34=3648=45.5 \text{Mean} = \frac{43 + 54 + 55 + 55 + 55 + 34 + 34 + 34}{8} = \frac{ 43 + 54 + 55 + 55 + 55 + 34 + 34 + 34 = 364 }{8} = 45.5

  4. Median Calculation: To find the median, we first need to sort the numbers: (34, 34, 34, 43, 54, 55, 55, 55). The median of this even data set is the average of the 4th and 5th numbers: Median=43+542=972=48.5 \text{Median} = \frac{43 + 54}{2} = \frac{97}{2} = 48.5

Verify and Summarize

  • The most frequent number (mode) in the data set is clearly identified as 55, which appears three times.
  • The mean is calculated to be 45.5, and the median is 48.5. Both are different from the mode.
  • Thus, the 55 is not just a raw score but specifically the mode of the data set.

Final Answer

b. Mode

This problem has been solved

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