To find the [H+] concentration, we first need to find the [OH-] concentration. Since KOH is a strong base, it will dissociate completely in water to form K+ and OH- ions. Therefore, the [OH-] concentration is the same as the molarity of the KOH solution, which is 6.8 x 10^-4 M.

Next, we use the ion product of water (Kw) to find the [H+] concentration. Kw is equal to [H+][OH-] and at 25 degrees Celsius, Kw is 1.0 x 10^-14.

So, we can set up the equation as follows:

[H+] = Kw / [OH-]
[H+] = 1.0 x 10^-14 / 6.8 x 10^-4

Solving this equation gives us the [H+] concentration.

Question

To find the [H+] concentration, we first need to find the [OH-] concentration. Since KOH is a strong base, it will dissociate completely in water to form K+ and OH- ions. Therefore, the [OH-] concentration is the same as the molarity of the KOH solution, which is 6.8 x 10^-4 M.

Next, we use the ion product of water (Kw) to find the [H+] concentration. Kw is equal to [H+][OH-] and at 25 degrees Celsius, Kw is 1.0 x 10^-14.

So, we can set up the equation as follows:

[H+] = Kw / [OH-]
[H+] = 1.0 x 10^-14 / 6.8 x 10^-4

Solving this equation gives us the [H+] concentration.

Knowee AI · Accepted Answer

To find the [H+] concentration, we first need to find the [OH-] concentration. Since KOH is a strong base, it will dissociate completely in water to form K+ and OH- ions. Therefore, the [OH-] concentration is the same as the molarity of the KOH solution, which is 6.8 x 10^-4 M.

Next, we use the ion product of water (Kw) to find the [H+] concentration. Kw is equal to [H+][OH-] and at 25 degrees Celsius, Kw is 1.0 x 10^-14.

So, we can set up the equation as follows:

[H+] = Kw / [OH-]
[H+] = 1.0 x 10^-14 / 6.8 x 10^-4

Solving this equation gives us the [H+] concentration.

Given KOH solution molarity: 6.8 x 10-4 MCalculate [H+] = ? M (H+ molarity)Group of answer choices6.8 x 10^-101.0 x 10^-147.2 x 10^-41.5 x 10^-11

Question

Given KOH solution molarity: 6.8 x 10^-4 M

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