The vibrational frequency, ν(OH), of a molecule is not expected to decrease upon dilution if the molecule does not form hydrogen bonds.

1. p-hydroxy benzoic acid: This molecule can form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

2. Acetic acid: This molecule can also form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

3. m-nitro phenol: This molecule can form strong intermolecular hydrogen bonds due to the presence of the -OH group and the -NO2 group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

4. o-hydroxy benzaldehyde: This molecule cannot form intermolecular hydrogen bonds due to the position of the -OH group and the absence of other groups that can form hydrogen bonds. Therefore, dilution is not expected to decrease ν(OH) for this molecule.

So, the vibrational frequency ν(OH) of o-hydroxy benzaldehyde will not decrease on dilution.

Question

The vibrational frequency, ν(OH), of a molecule is not expected to decrease upon dilution if the molecule does not form hydrogen bonds.

1. p-hydroxy benzoic acid: This molecule can form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

2. Acetic acid: This molecule can also form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

3. m-nitro phenol: This molecule can form strong intermolecular hydrogen bonds due to the presence of the -OH group and the -NO2 group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

4. o-hydroxy benzaldehyde: This molecule cannot form intermolecular hydrogen bonds due to the position of the -OH group and the absence of other groups that can form hydrogen bonds. Therefore, dilution is not expected to decrease ν(OH) for this molecule.

So, the vibrational frequency ν(OH) of o-hydroxy benzaldehyde will not decrease on dilution.

Knowee AI · Accepted Answer

The vibrational frequency, ν(OH), of a molecule is not expected to decrease upon dilution if the molecule does not form hydrogen bonds.

1. p-hydroxy benzoic acid: This molecule can form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

2. Acetic acid: This molecule can also form intermolecular hydrogen bonds due to the presence of the -OH group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

3. m-nitro phenol: This molecule can form strong intermolecular hydrogen bonds due to the presence of the -OH group and the -NO2 group. Therefore, dilution can disrupt these hydrogen bonds, leading to a decrease in ν(OH).

4. o-hydroxy benzaldehyde: This molecule cannot form intermolecular hydrogen bonds due to the position of the -OH group and the absence of other groups that can form hydrogen bonds. Therefore, dilution is not expected to decrease ν(OH) for this molecule.

So, the vibrational frequency ν(OH) of o-hydroxy benzaldehyde will not decrease on dilution.

For which molecule ν(OH) will not decrease on dilution?(1 Ponto)p- hydroxy benzoic acidAcetic acidm-nitro phenolo- hydroxy benzaldehyde

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For which molecule ν(OH) will not decrease on dilution?

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