What is the output of the following code?a = [1, 2, 3, 4]for x in a:    if x == 3:        break    print(x)121231234Error

The output of the given code will be:

1 2

Here's the step by step explanation:

1. The code starts by defining a list a with elements 1, 2, 3, 4.

2. Then it enters a for loop, where it will iterate over each element x in the list a.

3. For each iteration, it checks if x is equal to 3. If x is 3, it will break the loop and stop further execution.

4. If x is not equal to 3, it will print the value of x.

5. So, for the first iteration, x is 1, it's not equal to 3, so it prints 1.

6. In the second iteration, x is 2, it's not equal to 3, so it prints 2.

7. In the third iteration, x is 3, which is equal to 3, so it breaks the loop and stops further execution.

8. Therefore, the output of the code is 1 and 2, each printed on a new line.