The sum of three consecutive even numbers is 132. What is the smallest number?Options446444842
Question
The sum of three consecutive even numbers is 132. What is the smallest number?
Options:
- 44
- 64
- 48
- 42
Solution
Let's denote the three consecutive even numbers as n, n+2, and n+4.
According to the problem, the sum of these three numbers is 132. So, we can write the equation as:
n + (n+2) + (n+4) = 132
Solving this equation will give us the value of n, which is the smallest number.
Combine like terms:
3n + 6 = 132
Subtract 6 from both sides:
3n = 126
Divide both sides by 3:
n = 42
So, the smallest number is 42.
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