The sum of three numbers is 132. If the first number be twice the second and third number is one third of the first, then the second number is
Question
The sum of three numbers is 132. If the first number be twice the second and third number is one third of the first, then the second number is
Solution
Let's denote the three numbers as , , and .
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According to the problem, the sum of the three numbers is 132:
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The first number is twice the second number :
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The third number is one third of the first number :
Now, we substitute the expressions for and into the sum equation:
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Substitute and into :
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Combine the terms on the left side:
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Solve for :
Therefore, the second number is .
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