Calculate the Normality of the given 100ml barium chloride titrated against 20ml of 0.02N Sodium sulfatea.0.02b.0.002c.0.04d.0.004

To calculate the Normality of the barium chloride solution, we need to use the concept of Normality equation which is:

N1V1 = N2V2

Where: N1 = Normality of the solution 1 (Sodium sulfate in this case) V1 = Volume of the solution 1 (Sodium sulfate in this case) N2 = Normality of the solution 2 (Barium chloride in this case) V2 = Volume of the solution 2 (Barium chloride in this case)

Given: N1 = 0.02N (Normality of Sodium sulfate) V1 = 20ml (Volume of Sodium sulfate) V2 = 100ml (Volume of Barium chloride)

We need to find N2 (Normality of Barium chloride)

Substituting the given values in the equation:

0.02N * 20ml = N2 * 100ml

Solving for N2:

N2 = (0.02N * 20ml) / 100ml

N2 = 0.004N

So, the Normality of the Barium chloride solution is 0.004N. Therefore, the correct answer is (d) 0.004.