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The concentration of solute in a solution that contains 0.900 g of sodium chloride in 100 mL is __________ M.*1 point0.00990.01540.1540.000154

Question

The concentration of solute in a solution that contains 0.900 g of sodium chloride in 100 mL is __________ M.

1 point

  • 0.0099
  • 0.0154
  • 0.154
  • 0.000154
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Solution

To find the molarity (M) of the solution, we need to follow these steps:

  1. Convert the mass of the solute (sodium chloride, NaCl) from grams to moles. The molar mass of NaCl is approximately 58.44 g/mol. So, 0.900 g NaCl * (1 mol/58.44 g) = 0.0154 mol NaCl.

  2. Convert the volume of the solution from milliliters to liters. 100 mL = 0.1 L.

  3. Calculate the molarity by dividing the number of moles of solute by the volume of the solution in liters. M = 0.0154 mol / 0.1 L = 0.154 M.

So, the concentration of the solution is 0.154 M.

This problem has been solved

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