The third term of a G.P. is 12. The product of first five terms is _____.Choices:- 12^5 12^2 4^4 3^7
Question
The third term of a G.P. is 12. The product of first five terms is _____.
Choices:
12^5
12^2
4^4
3^7
Solution
In a geometric progression (G.P.), the third term is given by a*r^2, where 'a' is the first term and 'r' is the common ratio.
Given that the third term is 12, we have a*r^2 = 12.
The product of the first five terms of a G.P. is given by (ar^4)(ar^3)(ar^2)(ar)(a) = a^5 * r^10.
We know that a*r^2 = 12, so we can substitute this into the equation for the product of the first five terms to get (12)^5 = 248832.
Therefore, the product of the first five terms is 248832. However, this option is not available in the choices given.
There seems to be a mistake in the question or the choices provided.
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