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In how many ways can the 4 members of a club fill 2 different leadership positions, assuming that each member can only fill one position?

Question

In how many ways can the 4 members of a club fill 2 different leadership positions, assuming that each member can only fill one position?

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Solution

To solve this problem, we can use the concept of permutations.

Step 1: Identify the number of total members and the number of positions to be filled. In this case, we have 4 members and 2 positions.

Step 2: Use the formula for permutations, which is nPr = n! / (n - r)!. Here, n is the total number of items (or members), and r is the number of items to choose (or positions to fill).

Step 3: Substitute the values into the formula. So, we have 4P2 = 4! / (4 - 2)!

Step 4: Calculate the factorial values. 4! = 4 * 3 * 2 * 1 = 24 and (4 - 2)! = 2! = 2 * 1 = 2.

Step 5: Substitute the factorial values back into the formula. So, we have 4P2 = 24 / 2 = 12.

Therefore, there are 12 ways the 4 members of the club can fill the 2 different leadership positions.

This problem has been solved

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