StudyGPT Just Leveled Up – Say Hello to Knowee! 🚀
Knowee
Questions
Features
Study Tools

Ksp for X(OH)2 in a certain temperature equal (3.6x10-13), pH value for its saturated solution equals:

Question

Ksp for X(OH)2 in a certain temperature equal (3.6x10^-13), pH value for its saturated solution equals:

🧐 Not the exact question you are looking for?Go ask a question

Solution

To determine the pH value of a saturated solution of X(OH)2, we need to consider the dissociation of X(OH)2 in water.

The dissociation of X(OH)2 can be represented by the equation: X(OH)2 ⇌ X2+ + 2OH-

The equilibrium constant for this dissociation reaction is known as the solubility product constant, Ksp. In this case, the Ksp for X(OH)2 is given as 3.6x10-13.

Since X(OH)2 dissociates into X2+ and 2OH-, we can assume that the concentration of X2+ is equal to the concentration of OH- in the saturated solution. Let's represent the concentration of X2+ and OH- as [X2+] and [OH-], respectively.

Using the stoichiometry of the dissociation reaction, we can write the expression for Ksp as: Ksp = [X2+][OH-]^2

Since [X2+] = [OH-], we can substitute [X2+] with [OH-] in the Ksp expression: Ksp = [OH-][OH-]^2 Ksp = [OH-]^3

Now, we can solve for [OH-] by taking the cube root of Ksp: [OH-] = (Ksp)^(1/3) [OH-] = (3.6x10-13)^(1/3)

Finally, to find the pH value of the saturated solution, we need to calculate the concentration of H+ ions. Since water undergoes autoionization to produce equal concentrations of H+ and OH- ions, the concentration of H+ is also equal to [OH-].

Therefore, the pH value of the saturated solution of X(OH)2 is equal to the negative logarithm (base 10) of the concentration of H+ ions, which is equal to [OH-].

pH = -log[H+] pH = -log[OH-] pH = -log((3.6x10-13)^(1/3))

By evaluating this expression, you can find the pH value for the saturated solution of X(OH)2 at the given temperature.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.