A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and = 1.6 × 10–5 M Ksp of Ca3(PO4)2 is :-3.2 × 10–133.2 × 10–342.048 × 10–333.2 × 10–15
Question
Solution 1
The solubility product constant, Ksp, can be calculated using the concentrations of the ions in a saturated solution. The formula for calcium phosphate is Ca3(PO4)2, which means that in a saturated solution, one formula unit dissociates into 3 Ca2+ ions and 2 PO43- ions.
The Ksp expression for Ca3( Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and = 1.6 × 10–5 M Ksp of Ca3(PO4)2 is :-3.2 × 10–133.2 × 10–342.048 × 10–333.2 × 10–15
Ksp for X(OH)2 in a certain temperature equal (3.6x10-13), pH value for its saturated solution equals:
100 ml of a saturated solution of Mg(OH)2 contains 8.2 10-4 g solute. Mol. wt. of Mg(OH)2 is 58.3 g mole-1; calculate its Ksp.
Ksp of CaF2 is 1.7 10-10 and its mol. wt. is 78 g mole-1. What volume of the saturated solution will contain 0.078 g of CaF2?
If the solubility product of Mg3(PO4)2 equals 1.08x10-13, what is the value of [Mg2+] in the saturated solution?