A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and = 1.6 × 10–5 M Ksp of Ca3(PO4)2 is :-3.2 × 10–133.2 × 10–342.048 × 10–333.2 × 10–15
Question
A saturated solution of Ca3(PO4)2 has[Ca2+] = 2 × 10–8 M and = 1.6 × 10–5 M
Ksp of Ca3(PO4)2 is :-
- 3.2 × 10–1
- 3.2 × 10–3
- 2.048 × 10–3
- 3.2 × 10–15
Solution
The solubility product constant, Ksp, can be calculated using the concentrations of the ions in a saturated solution. The formula for calcium phosphate is Ca3(PO4)2, which means that in a saturated solution, one formula unit dissociates into 3 Ca2+ ions and 2 PO43- ions.
The Ksp expression for Ca3(PO4)2 is:
Ksp = [Ca2+]^3 * [PO4^3-]^2
Given that [Ca2+] = 2 × 10–8 M and [PO4^3-] = 1.6 × 10–5 M, we can substitute these values into the Ksp expression:
Ksp = (2 × 10–8)^3 * (1.6 × 10–5)^2
= 8 × 10–24 * 2.56 × 10–10
= 2.048 × 10–33
So, the Ksp of Ca3(PO4)2 is 2.048 × 10–33.
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