Implement a function that returns an updated array with 1 left rotation on an array of integersrotateLeft([1,2,3,4]) // returns [2,3,4,1]

Step 1: Break Down the Problem

We need to implement a function that performs a left rotation on an array of integers. A left rotation means that each element of the array is shifted left, and the first element wraps around to the end of the array.

Step 2: Relevant Concepts

1. Understanding Left Rotation: For an array [1, 2, 3, 4], a left rotation will move each element to the left by one position, yielding [2, 3, 4, 1].
2. Array Manipulation: We can achieve this by slicing the array into two parts and rearranging them.

Step 3: Analysis and Detail

1. Take the first element of the array and store it.
2. Create a new array by slicing the original array from the first index to the end.
3. Append the stored first element to the end of the new array.

Step 4: Verify and Summarize

Verify the rotation by running a function and checking the output.

Final Answer

Here's the implementation in Python:

def rotateLeft(arr):
    if len(arr) == 0:
        return arr  # Handle empty array
    return arr[1:] + [arr[0]]

# Example Usage
result = rotateLeft([1, 2, 3, 4])
print(result)  # Output: [2, 3, 4, 1]

This function takes an array and returns the updated array after performing one left rotation.