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What will the following code print?counter = 1sum = 0while counter <= 6:    counter = counter + 2    sum = sum + counterprint(sum)

Question

What will the following code print?

counter = 1
sum = 0
while counter &lt;= 6:
    counter = counter + 2
    sum = sum + counter
print(sum)
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Solution

The code is written in Python and it's a simple loop that increments a counter and a sum.

Here's a step-by-step breakdown:

  1. Two variables are initialized: counter is set to 1 and sum is set to 0.

  2. The while loop will run as long as counter is less than or equal to 6.

  3. Inside the loop, counter is incremented by 2 each time the loop runs.

  4. Also inside the loop, the new value of counter is added to sum.

  5. Once the loop finishes running, the final value of sum is printed.

Let's go through the loop:

  • In the first iteration, counter is 1. It's incremented by 2, so counter becomes 3. This is added to sum, so sum is now 3.

  • In the second iteration, counter is 3. It's incremented by 2, so counter becomes 5. This is added to sum, so sum is now 8.

  • In the third iteration, counter is 5. It's incremented by 2, so counter becomes 7. This is added to sum, so sum is now 15.

  • Now counter is 7, which is more than 6, so the loop stops running.

The final value of sum is 15, so the code will print 15.

This problem has been solved

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