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Study the following program:i = 0while i < 3:       print(i)       i += 1 else:      print(0)  0 10 1 20 1 2 00 1 2 3

Question

Study the following program:

i = 0
while i &lt; 3: 
    print(i) 
    i += 1 
else: 
    print(0)

0
10
1
20
1
2
00
1
2
3

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Solution

The program you provided is written in Python. Here's a step-by-step explanation of how it works:

  1. The variable i is initialized with a value of 0.

  2. The while loop checks if the value of i is less than 3. If it is, it enters the loop.

  3. Inside the loop, it first prints the current value of i.

  4. Then, it increments the value of i by 1 using the += operator.

  5. The loop then goes back to the condition check. If i is still less than 3, it repeats steps 3 and 4. If i is not less than 3, it exits the loop.

  6. After the loop, the else statement is executed. This happens when the while loop condition is no longer true. It prints the value 0.

  7. The final output of the program will be:

0
1
2
0

The numbers 0, 1, and 2 are printed from the while loop, and the final 0 is printed from the else statement after the loop.

This problem has been solved

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