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What is the speed ratio (vA/vB) if particle A has 7 times the kinetic energy and half the mass of particle B? 0.267 1.87 3.74 2.65

Question

What is the speed ratio (vA/vB) if particle A has 7 times the kinetic energy and half the mass of particle B?

  • 0.267
  • 1.87
  • 3.74
  • 2.65
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Solution

The kinetic energy (KE) of a particle is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity of the particle.

Given that particle A has 7 times the kinetic energy of particle B, we can write:

7 * (1/2 * mB * vB^2) = 1/2 * mA * vA^2

Given that particle A has half the mass of particle B, we can substitute mA = 1/2 * mB into the equation:

7 * (1/2 * mB * vB^2) = 1/2 * (1/2 * mB) * vA^2

Solving for vA/vB gives:

vA/vB = sqrt(14) = 3.74

So, the speed ratio (vA/vB) is 3.74.

This problem has been solved

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