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A vessel contains 16 g of hydrogen and 128 g of oxygen at standard temperature and pressure. Findthe volume of the vessel in cm3

Question

A vessel contains 16 g of hydrogen and 128 g of oxygen at standard temperature and pressure. Find the volume of the vessel in cm³.

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Solution

To find the volume of the vessel, we can use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

First, we need to calculate the number of moles of hydrogen and oxygen in the vessel. To do this, we can use the molar mass of each gas.

The molar mass of hydrogen (H2) is 2 g/mol, and the molar mass of oxygen (O2) is 32 g/mol.

For hydrogen: Number of moles = mass / molar mass Number of moles = 16 g / 2 g/mol Number of moles = 8 mol

For oxygen: Number of moles = mass / molar mass Number of moles = 128 g / 32 g/mol Number of moles = 4 mol

Now that we have the number of moles of each gas, we can calculate the total number of moles in the vessel: Total moles = moles of hydrogen + moles of oxygen Total moles = 8 mol + 4 mol Total moles = 12 mol

Next, we need to convert the temperature to Kelvin. Standard temperature is 273.15 K.

Now we can rearrange the ideal gas law equation to solve for volume: V = (nRT) / P

Substituting the values we have: V = (12 mol * 0.0821 L/mol*K * 273.15 K) / 1 atm

Simplifying the equation: V = 27.9 L

Finally, we need to convert the volume from liters to cm3: 1 L = 1000 cm3

Converting the volume: V = 27.9 L * 1000 cm3/L V = 27,900 cm3

Therefore, the volume of the vessel is 27,900 cm3.

This problem has been solved

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