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Problem statementSend feedbackint a = 7;int b = 17;int *c = &b;*c = 7;cout << a << " “ << b << endl;

Question

Problem Statement

int a = 7;
int b = 17;
int *c = &amp;b;
*c = 7;
cout &lt;&lt; a &lt;&lt; &quot;  &quot; &lt;&lt; b &lt;&lt; endl;
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Solution

The code you've written is in C++. Here's a step-by-step explanation of what it does:

  1. int a = 7; This line declares an integer variable a and assigns it the value 7.

  2. int b = 17; This line declares an integer variable b and assigns it the value 17.

  3. int *c = &b; This line declares a pointer c and assigns it the address of b. This means c is pointing to b.

  4. *c = 7; This line changes the value at the address pointed to by c to 7. Since c is pointing to b, this effectively changes the value of b to 7.

  5. cout << a << " “ << b << endl; This line prints the values of a and b to the console. Since b's value was changed to 7 in the previous step, the output will be 7 7.

This problem has been solved

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