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What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int i;for (i = 0; i < 5; i++)    arr[i] = arr[i] + 2;printf("%d\n", arr[3]);

Question

What is the output of the following code?

int arr[] = {1, 2, 3, 4, 5};
int i;
for (i = 0; i &lt; 5; i++)
    arr[i] = arr[i] + 2;
printf(&quot;%d\n&quot;, arr[3]);
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Solution

The output of the code will be 6.

Here's the step by step explanation:

  1. An integer array arr is declared and initialized with the values {1, 2, 3, 4, 5}.

  2. A for loop is set up to iterate over the array from the first element (at index 0) to the last element (at index 4).

  3. Inside the loop, each element of the array is incremented by 2. So, the array becomes {3, 4, 5, 6, 7}.

  4. After the loop, the value of the element at index 3 (which is the fourth element) of the array is printed. Since arrays are 0-indexed, arr[3] refers to the fourth element of the array, which is 6.

So, the output of the code is 6.

This problem has been solved

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