Find the zeroes of the quadratic polynomial2 11 27 3 3y y  and verify the relationship between thezeroes and the coefficients

To find the zeroes of the quadratic polynomial 2y^2 + 11y + 27, we can use the quadratic formula. The quadratic formula states that for a quadratic equation of the form ax^2 + bx + c = 0, the zeroes can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, the coefficients are a = 2, b = 11, and c = 27. Plugging these values into the quadratic formula, we get:

y = (-11 ± √(11^2 - 4(2)(27))) / (2(2))

Simplifying further, we have:

y = (-11 ± √(121 - 216)) / 4 y = (-11 ± √(-95)) / 4

Since we have a negative value under the square root, it means that the quadratic polynomial has no real zeroes. The relationship between the zeroes and the coefficients in this case is that there are no zeroes.