Se mezclan 50 gramos de cloruro de sodio (NaCl) con 150 gramos de agua. Calcule la concentración molar (M) de la solución.*1 punto0.856 M.58.44 M.4.28 M.

1. Break Down the Problem

To calculate the molar concentration (M) of the sodium chloride (NaCl) solution, we need to determine:

1. The number of moles of NaCl.
2. The volume of the solvent (water in liters).

2. Relevant Concepts

The molarity (M) is given by the formula:

$M = \frac{\text{moles of solute}}{\text{liters of solution}}$

To find the moles of solute (NaCl), we use the molar mass of NaCl:

$\text{Molar mass of NaCl} = \text{Molar mass of Na} + \text{Molar mass of Cl} = 22.99 \, \text{g/mol} + 35.45 \, \text{g/mol} = 58.44 \, \text{g/mol}$

3. Analysis and Detail

1. Calculate Moles of NaCl: $\text{Moles of NaCl} = \frac{\text{mass of NaCl}}{\text{molar mass of NaCl}} = \frac{50 \, \text{g}}{58.44 \, \text{g/mol}} \approx 0.856 \, \text{moles}$

2. Calculate the Total Volume of the Solution: Assuming the volume of the NaCl is negligible compared to the water, we calculate the volume of the water:

   • The density of water is approximately $1 \, \text{g/mL}$, so $150 \, \text{g}$ of water is equivalent to $150 \, \text{mL}$ or $0.150 \, \text{L}$.

3. Calculate the Molar Concentration (M): $M = \frac{\text{moles of NaCl}}{\text{liters of solution}} = \frac{0.856 \, \text{moles}}{0.150 \, \text{L}} \approx 5.707 \, \text{M}$

4. Verify and Summarize

The calculations show that the concentration is approximately $5.707 \, \text{M}$. However, this result does not match any of the provided options. The closest choice within a reasonable rounding could indicate a problem interpretation error or value ranges in choices.

Final Answer

The calculated concentration of the solution is approximately $5.707 \, \text{M}$, which is not listed in the options. Please verify the options or parameters provided.