Find the largest number which divides 62, 132, 237 to leave the same remainder in each case?a.34b.35c.32d.33
Question
Find the largest number which divides 62, 132, 237 to leave the same remainder in each case?
a. 34
b. 35
c. 32
d. 33
Solution
To solve this problem, we need to find the difference between each pair of numbers and then find the greatest common divisor (GCD) of those differences.
The differences are:
- 132 - 62 = 70
- 237 - 132 = 105
- 237 - 62 = 175
Now, we need to find the GCD of 70, 105, and 175. The GCD of these numbers is 35.
So, the largest number which divides 62, 132, 237 to leave the same remainder in each case is 35. Therefore, the answer is (b) 35.
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