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If xyz represents a three-digit number then xyzxyz is always divisible by:Options11 only7, 11 and 137 only11 and 13 only

Question

If xyz represents a three-digit number then xyzxyz is always divisible by:

Options:

  • 11 only
  • 7, 11 and 137 only
  • 11 and 13 only
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Solution

Break Down the Problem

  1. We need to analyze the number xyzxyz xyzxyz which can be represented mathematically.
  2. Determine the divisibility of xyzxyz xyzxyz by the given options.

Relevant Concepts

  1. xyz xyz is a three-digit number which can be expressed as 100x+10y+z 100x + 10y + z .
  2. Thus, xyzxyz xyzxyz can be expressed as: xyzxyz=1000xyz+xyz=1001×xyz xyzxyz = 1000xyz + xyz = 1001 \times xyz

Analysis and Detail

  1. Since xyzxyz=1001×xyz xyzxyz = 1001 \times xyz , we need to find the prime factorization of 1001 1001 : 1001=7×11×13 1001 = 7 \times 11 \times 13
  2. Therefore, xyzxyz xyzxyz is divisible by 7 7 , 11 11 , and 13 13 .

Verify and Summarize

  1. We have confirmed that xyzxyz xyzxyz , which is 1001×xyz 1001 \times xyz , is divisible by 7 7 , 11 11 , and 13 13 since 1001 1001 has these numbers as its factors.
  2. Among the options provided, the one that states 7,11, and 137 7, 11, \text{ and } 137 is incorrect because 137 137 is not a factor of 1001 1001 .

Final Answer

The correct answer is that xyzxyz xyzxyz is always divisible by 7, 11, and 13 only.

This problem has been solved

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